M
your problem I think is that your file doesn’t fill the rom completely
Size: a a a
2019 May 06
M
leaving it partially initialized
RZ
```
initial begin
$readmemh (“path/file.wav”, rom);
end
```
initial begin
$readmemh (“path/file.wav”, rom);
end
```
Yes, exactly. I just don't remember the exact code. But I will show the full code. Later
M
and this is considered an error
RZ
Error: non-hex symbol "r" in .wav file
M
one moment
M
DIDN’T you convert your file to hex file?
RZ
But how?
M
an hex file is just a text file in which each line has an hex number that goes to a memory cell
M
I use a small C program
M
do you know how to compile a C program?
RZ
do you know how to compile a C program?
Yes, thank you very much! I will try it!
M
Yes, thank you very much! I will try it!
Here you have mine. Usage is:
bin2hex filename.wav (for example) and it will create filename.wav.hex
bin2hex filename.wav (for example) and it will create filename.wav.hex
M
Thanks!
One more thing:
your ROM must be completely initialized. Your WAV file most probably won't fill it, so you have to preinitialize it with zeros, and then, load your hex file, like this:
logic [7:0] rom[0:4095];
integer i;
initial begin
for (i=0;i<4096;i=i+1)
rom[i] = 8'h00;
$readmemh ("path/file.wav.hex", rom);
end
And, of course, unless you have a FPGA with lots of block memory, you want your wav files to be small enough so the FPGA can use its block memory to store them.
your ROM must be completely initialized. Your WAV file most probably won't fill it, so you have to preinitialize it with zeros, and then, load your hex file, like this:
logic [7:0] rom[0:4095];
integer i;
initial begin
for (i=0;i<4096;i=i+1)
rom[i] = 8'h00;
$readmemh ("path/file.wav.hex", rom);
end
And, of course, unless you have a FPGA with lots of block memory, you want your wav files to be small enough so the FPGA can use its block memory to store them.
RZ
One more thing:
your ROM must be completely initialized. Your WAV file most probably won't fill it, so you have to preinitialize it with zeros, and then, load your hex file, like this:
logic [7:0] rom[0:4095];
integer i;
initial begin
for (i=0;i<4096;i=i+1)
rom[i] = 8'h00;
$readmemh ("path/file.wav.hex", rom);
end
And, of course, unless you have a FPGA with lots of block memory, you want your wav files to be small enough so the FPGA can use its block memory to store them.
your ROM must be completely initialized. Your WAV file most probably won't fill it, so you have to preinitialize it with zeros, and then, load your hex file, like this:
logic [7:0] rom[0:4095];
integer i;
initial begin
for (i=0;i<4096;i=i+1)
rom[i] = 8'h00;
$readmemh ("path/file.wav.hex", rom);
end
And, of course, unless you have a FPGA with lots of block memory, you want your wav files to be small enough so the FPGA can use its block memory to store them.
Thank you, I didn't know about initialization with 0.
2019 May 07
IK
It depends on what synchronous logic structure you use. You should elaborate your question more if you want more precise answer.
2019 May 08
ΔΒ
if( reset && sel=2 )
begin
end
else if( reset && sel==1 )
begin
end