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syn::Path вида Foo<Bar, Baz> в Foo::<Bar, Baz>?в🧇
syn::Path вида Foo<Bar, Baz> в Foo::<Bar, Baz>?syn
>> простой♚
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make(vec![1,2,3]) == vec![[], [1], [2], [3], [1,2], [1,3], [2,3], [1,2,3]]KB
make(vec![1,2,3]) == vec![[], [1], [2], [3], [1,2], [1,3], [2,3], [1,2,3]]p