S
TQ.. so much
Size: a a a
2022 February 12
S
Sir
A
👍👍
S
Using imap mail message Iam getting this message
S
S
I have given the ID and password correctly
T
Credentials fails that means it credentials issue.. check again
VR
Interested
VR
Jon interested
S
I have used my gmail user ID and password
Both in string
Both in string
AP
Required RPA Uipath Trainer
AP
4 members are there
AP
If you're interested contact me
Anitha
Anitha
A
Have you check your imap settings for gmail account?
S
Hi, everyone
S
For get a string form the name of a file, I usually use CurrentFile.Name
The problem is: it also gets the file extension of the file.
How do I can get the filename without the extension? (eg.: FileName.txt -> FileName)
The problem is: it also gets the file extension of the file.
How do I can get the filename without the extension? (eg.: FileName.txt -> FileName)
R
Split it based on .
VD
use variable with type FileInfo like:
fInfo = new System.IO.FileInfo(«Filename»)
fInfo.Name.Replace(fInfo.Extension, «»)
fInfo = new System.IO.FileInfo(«Filename»)
fInfo.Name.Replace(fInfo.Extension, «»)
S
Do I have to use "Write line" for this?
S
