I have a question related to a button that when clicking, it takes me to another page. How do I do this with scrapy?

before that, login with login and password authentication. This I managed to do, now inside the site I need to click on that button and it takes me to a page.

F12 -> Network
See the requests that go to the page.
But, this is not always required. Most often, you can skip this step and immediately request a page with the data.

scrapy.httpRequest - for GET requests: https://docs.scrapy.org/en/latest/topics/request-response.html#request-objects
scrapy.http.FormRequest  - for POST requests: https://docs.scrapy.org/en/latest/topics/request-response.html#formrequest-objects

The button calls POST or GET request

I hope I'm writing clearly. :))
Using translator

button behavior is get request

ok

yield scrapy.Request(url='some url', callback=self.some_callback_func)

link, which you must go, is known for?

I did this with selenium webdriver, but there when I put login and password and click, I request the url directly with driver.get ("https: // URL")

ok, have you already logged in through scrapie? Or does the request for authorization need the same?

@trefto , @wrar42 - спасите-помогите, знаний языка не хватает 😂

я ничо не понял :))

Вроде нужно нажать на кнопку чтоб куда-то перебросило

я то же  :).
человеку хочет "кликнуть по кнопке после авторизации", но, я не пойму, он сам запрос на авторизацию сделал или нет

Yes, I managed to log in

о, авторизовался, помогите человеку :)

so, just send another request from the login callback

which command would I give?

you are using selenium, right? Are you using scrapy+selenium or pure selenium?

I have the code in selenium, now I'm doing it with pure scrapy

okay, then you should send the first request for login, after that send another request form login's callback

import scrapy

class BotEcacSpider(scrapy.Spider):
   name = 'bot_ecac'

   start_urls = ['https://cav.receita.fazenda.gov.br/autenticacao/login']


   def parse(self, response, **kwargs):

       return scrapy.FormRequest.from_response(
           response,
           formdata={
               'NI': '*******',
               'Senha': '*******',
               'CodigoAcesso': '********',
           },
           callback=self.after_login

       )

   def after_login(self, response):
       response.meta.get("https://www3.cav.receita.fazenda.gov.br/extratodirpf/#/")
       title = response.xpath('//*[@id="informacao-perfil"]/div[1]/span/text()').get()
       print(title)