d
Size: a a a
d
ВЩ
T
Y
ВЩ
K
Y
a = {1: -0.5672609400324171, 2: -3.461841070023597}K
K
U
Y
Y
K
Y
d
U
a = [{1: -0.5672609400324171, 2: -3.461841070023597},
{1: -30.5672609400324171, 2: -4.461841070023597},
{1: -4.5672609400324171, 2: -5.461841070023597},
{1: -6.5672609400324171, 2: -6.461841070023597},
{1: -3.5672609400324171, 2: -7.461841070023597}]
b = {3: -1.461841070023597}
c = [{1: -0.5672609400324171, 2: -3.461841070023597,3: -1.461841070023597},
{1: -30.5672609400324171, 2: -4.461841070023597,3: -1.461841070023597},
{1: -4.5672609400324171, 2: -5.461841070023597,3: -1.461841070023597},
{1: -6.5672609400324171, 2: -6.461841070023597,3: -1.461841070023597},
{1: -3.5672609400324171, 2: -7.461841070023597,3: -1.461841070023597}]
как из а и б получить с?T
ВЩ
for thing in a:
thing.update(b)
ВЩ
a = [{**thing, **b} for thing in a]ВЩ