ЖС
Size: a a a
ЖС
VA
VA
py3
import array
print(array.array('l', [1, 2, 3, 4, 5]))
array('l', [1, 2, 3, 4, 5])
VA
VA
<Ч
py3
import array
print(array.array('l', [1, 2, 3, 4, 5]))
array('l', [1, 2, 3, 4, 5])
VA
VA
<Ч
py3
import array
print(array.array('l', [1, 2, 3, 4, 5]))
array('l', [1, 2, 3, 4, 5])
VA
<Ч
S
df['Phone No_'].apply(lambda row: row[1:] if '+' in row)
File "<ipython-input-10-3da0be5464cf>", line 1
df['Phone No_'].apply(lambda row: row[1:] if '+' in row)
^
SyntaxError: invalid syntax
N
df['Phone No_'].apply(lambda row: row[1:] if '+' in row)
File "<ipython-input-10-3da0be5464cf>", line 1
df['Phone No_'].apply(lambda row: row[1:] if '+' in row)
^
SyntaxError: invalid syntax
S
Р
df['Phone No_'].apply(lambda row: row[1:] if '+' in row)
File "<ipython-input-10-3da0be5464cf>", line 1
df['Phone No_'].apply(lambda row: row[1:] if '+' in row)
^
SyntaxError: invalid syntax
N
VA
df['Phone No_'].apply(lambda row: row[1:] if '+' in row)
File "<ipython-input-10-3da0be5464cf>", line 1
df['Phone No_'].apply(lambda row: row[1:] if '+' in row)
^
SyntaxError: invalid syntax
S
K
v