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2020 January 24
AS
костыли пофиг на чем писать
AS
питон нормально для этого /s
АА
r
собстна он оттуда и пришёл сюда)
в сообщ с 51к чел куда вероятней получить ответ, да еще на англ, чем тут ))
АА
я сначала подумал может это тролль такой, который спамит со своим вопросом)
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Аlisher Temirov
I needn't break
SA
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Hi Harry. Sorry for the question. But what are you trying to do?
SA
In your example you just printing numbers from 0 to 3. Btw, you can just use
break instead of changing i..
Hi Harry. Sorry for the question. But what are you trying to do?
// C++, there's two times loops
for(int i = 0; i < 4; i ++)
if(i == 1)
i = 8;
// Python, there's four times loops
for i in range(4):
if i == 1:
i = 8
for(int i = 0; i < 4; i ++)
if(i == 1)
i = 8;
// Python, there's four times loops
for i in range(4):
if i == 1:
i = 8
.
.
// C++, there's two times loops
for(int i = 0; i < 4; i ++)
if(i == 1)
i = 8;
// Python, there's four times loops
for i in range(4):
if i == 1:
i = 8
for(int i = 0; i < 4; i ++)
if(i == 1)
i = 8;
// Python, there's four times loops
for i in range(4):
if i == 1:
i = 8
I'm gonna convert c++ code to python, but it doesn't work
SA
.
// C++, there's two times loops
for(int i = 0; i < 4; i ++)
if(i == 1)
i = 8;
// Python, there's four times loops
for i in range(4):
if i == 1:
i = 8
for(int i = 0; i < 4; i ++)
if(i == 1)
i = 8;
// Python, there's four times loops
for i in range(4):
if i == 1:
i = 8
Because in c++ implementation condition checks
i variable, but in python implementation you are using range(4) iterator which will generate numbers from 0 to 3 included. So in python assigning i = 8 will not affect loop.SA
They have little bit different mechanic.
.
Because in c++ implementation condition checks
i variable, but in python implementation you are using range(4) iterator which will generate numbers from 0 to 3 included. So in python assigning i = 8 will not affect loop.so, how can I do it?
SA
As I already said, you are using assignment to exit the loop. But better approach will be using the break statement
SA
So just replace "i = 8" with "break"
SA
Make sense?
.
As I already said, you are using assignment to exit the loop. But better approach will be using the break statement
is there another way? because I really needn't break
SA
.
is there another way? because I really needn't break
To offer you the better approach. Can you explain me the logic of your code? Because right now it's just changing the loop variable which leads the exit from loop.